en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-4/x y= 5/x

Solution

y^{^{'}} - \frac{4}{x} y = \frac{5}{x}

Solution

y = \frac{c _{1} x ^{4}}{4} - \frac{5}{4}

Solution steps

y^{'} (x) - \frac{4}{x} y = \frac{5}{x}

Solve separable ODE:

y = \frac{c _{1} x ^{4}}{4} - \frac{5}{4}

y = \frac{c _{1} x ^{4}}{4} - \frac{5}{4}

Popular Examples

y^{^{'}} = \frac{π}{y}

(dy}{dx}=-\frac{sin(x+5))/y

\frac{d y}{d x} = - \frac{sin ( x + 5 )}{y}

-x*f(x)=(df)/(dx)

- x \cdot f (x) = \frac{df}{d x}

(dx}{dt}=\frac{t+sin^2(t))/x ,x(0)=1

\frac{d x}{d t} = \frac{t + sin ^{2} ( t )}{x}, x (0) = 1

(dy)/(dx)=0.9(y-300)

\frac{d y}{d x} = 0.9 (y - 300)

Frequently Asked Questions (FAQ)

What is the solution for y^'-4/x y= 5/x ?
The solution for y^'-4/x y= 5/x is y=(c_{1}x^4)/4-5/4