What is the solution for (dy)/(dx)+9xy=8x,y(0)=2 ?

The solution for (dy)/(dx)+9xy=8x,y(0)=2 is y=(10e^{-(9x^2)/2})/(9)+8/9

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(dy)/(dx)+9xy=8x,y(0)=2

\frac{d y}{d x} + 9 x y = 8 x, y (0) = 2

y = \frac{10 e ^{- \frac{9 x ^{2}}{2}}}{9} + \frac{8}{9}

Solution steps

\frac{d y}{d x} + 9 x y = 8 x

Solve separable ODE:

y = \frac{10 e ^{- \frac{9 x ^{2}}{2}}}{9} + \frac{8}{9}

y = \frac{10 e ^{- \frac{9 x ^{2}}{2}}}{9} + \frac{8}{9}

\frac{d y}{d x} + 9 x y = 8 x, y (0) = 5

x^{^{'}} = a x (1 - \frac{x}{k})

y^{^{'}} sin^{2} (x) = cos (x) (1 - 3 y)

y^{^{'}} = \frac{( cos ^{2} ( x ) )}{y}

y^{^{'}} = \frac{y + 5}{7 t + 50}, y (2) = 0

What is the solution for (dy)/(dx)+9xy=8x,y(0)=2 ?
The solution for (dy)/(dx)+9xy=8x,y(0)=2 is y=(10e^{-(9x^2)/2})/(9)+8/9