What is the solution for (dy)/(dx)=yx^3-1.5y ?

The solution for (dy)/(dx)=yx^3-1.5y is y=e^{0.25x^4-1.5x+c_{1}}

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(dy)/(dx)=yx^3-1.5y

\frac{d y}{d x} = y x^{3} - 1.5 y

y = e^{0.25 x^{4} - 1.5 x + c_{1}}

Solution steps

\frac{d y}{d x} = y x^{3} - 1.5 y

Solve separable ODE:

y = e^{0.25 x^{4} - 1.5 x + c_{1}}

y = e^{0.25 x^{4} - 1.5 x + c_{1}}

\frac{d}{d x} ((y) \cdot 2) = 2 \cdot 10 - 3 y

y^{^{'}} + \frac{y}{4} = 4, y (- 3) = 0

(2 x + 3)^{4} = 3 y^{4} \frac{d y}{d x}

\frac{d y}{d x} = - \frac{4}{6} x^{8} y^{6}

(2 x - 1) y^{^{'}} - 2 y = 0 \frac{1 - 4 x}{x ^{2}}

What is the solution for (dy)/(dx)=yx^3-1.5y ?
The solution for (dy)/(dx)=yx^3-1.5y is y=e^{0.25x^4-1.5x+c_{1}}