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Popular >

(dy)/(dt)=y^2(8+t)

Solution

\frac{d y}{d t} = y^{2} (8 + t)

Solution

y = - \frac{2}{16 t + t ^{2} + c _{1}}

Solution steps

\frac{d y}{d t} = y^{2} (8 + t)

Solve separable ODE:

y = - \frac{2}{16 t + t ^{2} + c _{1}}

y = - \frac{2}{16 t + t ^{2} + c _{1}}

Graph

Popular Examples

y^{^{'}} y = y^{2}

(dy}{dx}=\frac{sqrt(xy^2))/x

\frac{d y}{d x} = \frac{x y ^{2}}{x}

(2+cos(t))((dy)/(dt))-ysin(t)=0

(2 + cos (t)) (\frac{d y}{d t}) - y sin (t) = 0

ay^'=-by^2-c,y(0)=5

a y^{^{'}} = - b y^{2} - c, y (0) = 5

(dy)/(dx)y=x^{-3}6cos(x)

\frac{d y}{d x} y = x^{- 3} 6 cos (x)

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dt)=y^2(8+t) ?
The solution for (dy)/(dt)=y^2(8+t) is y=-2/(16t+t^2+c_{1)}