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Popular >

y^'=-y+9

Solution

y^{^{'}} = - y + 9

Solution

y = e^{- t - c_{1}} + 9

Solution steps

y^{'} (t) = - y + 9

Solve separable ODE:

y = e^{- t - c_{1}} + 9

y = e^{- t - c_{1}} + 9

Popular Examples

sqrt(y)dx+(x-6)dy=0,y(7)=9

y d x + (x - 6) d y = 0, y (7) = 9

(dy)/(dx)2y^5=arctan(x)ln(x)

\frac{d y}{d x} 2 y^{5} = arctan (x) ln (x)

(3y2-t2y5)(dy)/(dt)+t2y4=0

(3 y 2 - t 2 y 5) \frac{d y}{d t} + t 2 y 4 = 0

y^{^{'}} = tan (x) y

(dy)/(dx)=e^{9y}+e^{(4x+9y)}

\frac{d y}{d x} = e^{9 y} + e^{(4 x + 9 y)}

Frequently Asked Questions (FAQ)

What is the solution for y^'=-y+9 ?
The solution for y^'=-y+9 is y=e^{-t-c_{1}}+9