What is the solution for (dy)/(dx)=(cos^2(y))/(4x-3) ?

The solution for (dy)/(dx)=(cos^2(y))/(4x-3) is y=arctan(1/4 ln(4x-3)+c_{1})+pin

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(dy)/(dx)=(cos^2(y))/(4x-3)

\frac{d y}{d x} = \frac{cos ^{2} ( y )}{4 x - 3}

y = arctan (\frac{1}{4} ln (4 x - 3) + c_{1}) + πn

Solution steps

\frac{d y}{d x} = \frac{cos ^{2} ( y )}{4 x - 3}

Solve separable ODE:

y = arctan (\frac{1}{4} ln (4 x - 3) + c_{1}) + πn

y = arctan (\frac{1}{4} ln (4 x - 3) + c_{1}) + πn

\frac{d p}{d t} = 5 p (20 - ln (p))

\frac{d y}{d x} + 2 x yy = 0, y (0) = - 1

(x^{2} - x^{2} y) d y + 2 x y d x = 0

y^{^{'}} - 3 y = 12, y (0) = 0

y^{^{'}} + \frac{( 1 0 ^{3} )}{4} y + 2 \cdot 1 0^{3} = 0

What is the solution for (dy)/(dx)=(cos^2(y))/(4x-3) ?
The solution for (dy)/(dx)=(cos^2(y))/(4x-3) is y=arctan(1/4 ln(4x-3)+c_{1})+pin