What is the solution for (dy)/(dx)+2xyy=0,y(0)=-1 ?

The solution for (dy)/(dx)+2xyy=0,y(0)=-1 is y=-1/(-x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+2xyy=0,y(0)=-1

\frac{d y}{d x} + 2 x yy = 0, y (0) = - 1

y = - \frac{1}{- x ^{2} + 1}

Solution steps

\frac{d y}{d x} + 2 x yy = 0

Solve separable ODE:

y = - \frac{1}{- x ^{2} + 1}

y = - \frac{1}{- x ^{2} + 1}

(x^{2} - x^{2} y) d y + 2 x y d x = 0

y^{^{'}} - 3 y = 12, y (0) = 0

y^{^{'}} + \frac{( 1 0 ^{3} )}{4} y + 2 \cdot 1 0^{3} = 0

\frac{d y}{d x} = 8 x 9 - y^{2}

e^{x^{2}} \frac{d y}{d x} - x y = 0

What is the solution for (dy)/(dx)+2xyy=0,y(0)=-1 ?
The solution for (dy)/(dx)+2xyy=0,y(0)=-1 is y=-1/(-x^2+1)