What is the solution for e^{x^2}(dy)/(dx)-xy=0 ?

The solution for e^{x^2}(dy)/(dx)-xy=0 is y=e^{-1/2 e^{-x^2}+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

e^{x^2}(dy)/(dx)-xy=0

e^{x^{2}} \frac{d y}{d x} - x y = 0

y = e^{- \frac{1}{2} e^{- x^{2}} + c_{1}}

Solution steps

e^{x^{2}} \frac{d y}{d x} - x y = 0

Solve separable ODE:

y = e^{- \frac{1}{2} e^{- x^{2}} + c_{1}}

y = e^{- \frac{1}{2} e^{- x^{2}} + c_{1}}

y^{^{'}} = \frac{x ^{2} - 2}{y}

y^{^{'}} + \frac{y ^{^{'}}}{x} + (1 - \frac{1}{4 x ^{2}}) y = 0

y y^{^{'}} - sin (x) = 0, y (π) = 1

csc (y) d y + sec^{2} (x) d x = 0

y^{^{'}} = \frac{3 x e ^{x}}{y 5 + y ^{2}}

What is the solution for e^{x^2}(dy)/(dx)-xy=0 ?
The solution for e^{x^2}(dy)/(dx)-xy=0 is y=e^{-1/2 e^{-x^2}+c_{1}}