What is the solution for ydx-xdy=2dy,y(1)=3 ?

The solution for ydx-xdy=2dy,y(1)=3 is y=e^{c_{1}}x+2e^{c_{1}}

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ydx-xdy=2dy,y(1)=3

y d x - x d y = 2 d y, y (1) = 3

y = e^{c_{1}} x + 2 e^{c_{1}}

Solution steps

y d x - x d y = 2 d y

Solve separable ODE:

y = e^{c_{1}} x + 2 e^{c_{1}}

y = e^{c_{1}} x + 2 e^{c_{1}}

(2 x + 1) \frac{d y}{d x} = 2 x y

\frac{d y}{d t} = y - 3

\frac{d y}{d x} = \frac{2 ^{3} + 1}{y}, y = 2, x = 2 y, x = 1

\frac{d y}{d x} = \frac{8}{y}

y^{^{'}} = \frac{( 2 t y )}{( 1 + y )}

What is the solution for ydx-xdy=2dy,y(1)=3 ?
The solution for ydx-xdy=2dy,y(1)=3 is y=e^{c_{1}}x+2e^{c_{1}}