What is the solution for (dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1 ?

The solution for (dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1 is y=sqrt(18x+c_{1)},y=-sqrt(18x+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1

\frac{d y}{d x} = \frac{2 ^{3} + 1}{y}, y = 2, x = 2 y, x = 1

y = 18 x + c_{1}, y = - 18 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{2 ^{3} + 1}{y}

Solve separable ODE:

y = 18 x + c_{1}, y = - 18 x + c_{1}

y = 18 x + c_{1}, y = - 18 x + c_{1}

\frac{d y}{d x} = \frac{8}{y}

y^{^{'}} = \frac{( 2 t y )}{( 1 + y )}

\frac{d y}{d t} = y + 5

(\frac{x + x}{y}) d x - d y = 0

\frac{d y}{d x} = (5 x y)

What is the solution for (dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1 ?
The solution for (dy}{dx}=\frac{2^3+1)/y ,y=2,x=2y,x=1 is y=sqrt(18x+c_{1)},y=-sqrt(18x+c_{1)}