What is the solution for ((x+x)/y)dx-dy=0 ?

The solution for ((x+x)/y)dx-dy=0 is y=sqrt(2x^2+c_{1)},y=-sqrt(2x^2+c_{1)}

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((x+x)/y)dx-dy=0

(\frac{x + x}{y}) d x - d y = 0

y = 2 x^{2} + c_{1}, y = - 2 x^{2} + c_{1}

Solution steps

(\frac{x + x}{y}) d x - d y = 0

Solve separable ODE:

y = 2 x^{2} + c_{1}, y = - 2 x^{2} + c_{1}

y = 2 x^{2} + c_{1}, y = - 2 x^{2} + c_{1}

\frac{d y}{d x} = (5 x y)

f^{^{'}} (x) = - 5 f (x)

y^{^{'}} = \frac{3 x - e ^{x}}{2 y - 5}

(1 + y^{2}) cos (x) d x = 2 (1 + sin^{2} (x)) y d y

y^{^{'}} = \frac{( y - 2 ) ^{2}}{x ^{2} + 1}, y (0) = 0

What is the solution for ((x+x)/y)dx-dy=0 ?
The solution for ((x+x)/y)dx-dy=0 is y=sqrt(2x^2+c_{1)},y=-sqrt(2x^2+c_{1)}