What is the solution for y^{''}+6y^'-7y=3e^{2x}-e^{-x} ?

The solution for y^{''}+6y^'-7y=3e^{2x}-e^{-x} is y=c_{1}e^x+c_{2}e^{-7x}+1/3 e^{2x}+1/12 e^{-x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+6y^'-7y=3e^{2x}-e^{-x}

y^{^{''}} + 6 y^{^{'}} - 7 y = 3 e^{2 x} - e^{- x}

y = c_{1} e^{x} + c_{2} e^{- 7 x} + \frac{1}{3} e^{2 x} + \frac{1}{12} e^{- x}

Solution steps

y^{''} (x) + 6 y^{'} (x) - 7 y = 3 e^{2 x} - e^{- x}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- 7 x} + \frac{1}{3} e^{2 x} + \frac{1}{12} e^{- x}

y = c_{1} e^{x} + c_{2} e^{- 7 x} + \frac{1}{3} e^{2 x} + \frac{1}{12} e^{- x}

\frac{d ^{2} y}{d x ^{2}} + \frac{d y}{d x} = tan (x)

y^{^{''}} - 2 y^{^{'}} - 3 y = 12 e^{x} - 6

y^{^{''}} + y = x cos (x) - cos (x)

y^{^{''}} - 10 y^{^{'}} + 9 y = 5 t

y^{^{''}} - 4 y^{^{'}} + 4 y = x^{3} e^{2 x} + x e^{2 x}

What is the solution for y^{''}+6y^'-7y=3e^{2x}-e^{-x} ?
The solution for y^{''}+6y^'-7y=3e^{2x}-e^{-x} is y=c_{1}e^x+c_{2}e^{-7x}+1/3 e^{2x}+1/12 e^{-x}