What is the derivative of x^2+3x+4 ?

The derivative of x^2+3x+4 is 2x+3

What is the first derivative of x^2+3x+4 ?

The first derivative of x^2+3x+4 is 2x+3

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derivative of

x^{2} + 3 x + 4

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 2 x + 3 + 0

Simplify

= 2 x + 3

\int x x + 8 d x

\int 0.0018 h^{2} d h

y = e^{3 x}, x = 0, x = 2

\frac{d}{d x} (- x cos (x) - x)

\frac{d}{d x} ((x^{3} + 7 x - 1) (5 x + 2))

What is the derivative of x^2+3x+4 ?
The derivative of x^2+3x+4 is 2x+3
What is the first derivative of x^2+3x+4 ?
The first derivative of x^2+3x+4 is 2x+3