What is the solution for x^{''}+9x=sin(2.9t) ?

The solution for x^{''}+9x=sin(2.9t) is x=c_{1}cos(3t)+c_{2}sin(3t)+1.69491…sin(2.9t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{''}+9x=sin(2.9t)

x^{^{''}} + 9 x = sin (2.9 t)

x = c_{1} cos (3 t) + c_{2} sin (3 t) + 1.69491 \dots sin (2.9 t)

Solution steps

x^{''} (t) + 9 x = sin (2.9 t)

Solve linear ODE:

x = c_{1} cos (3 t) + c_{2} sin (3 t) + 1.69491 \dots sin (2.9 t)

x = c_{1} cos (3 t) + c_{2} sin (3 t) + 1.69491 \dots sin (2.9 t)

y^{^{''}} - 7 y^{^{'}} + 12 y = 24

y^{^{''}} - 6 y^{^{'}} + 9 y = \frac{e ^{3 x}}{x}

y^{^{''}} - 2 y^{^{'}} + 10 y = sin (3 x) + cos (3 x)

y^{^{''}} - 4 y^{^{'}} + 13 y = e^{x} cos (x)

d (x) = 5 (\frac{1}{3})^{x}

What is the solution for x^{''}+9x=sin(2.9t) ?
The solution for x^{''}+9x=sin(2.9t) is x=c_{1}cos(3t)+c_{2}sin(3t)+1.69491…sin(2.9t)