What is (d^4)/(dx^4)(7e^{x^2}) ?

The answer to (d^4)/(dx^4)(7e^{x^2}) is 14(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})

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(d^4)/(dx^4)(7e^{x^2})

\frac{d ^{4}}{d x ^{4}} (7 e^{x^{2}})

14 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

Solution steps

\frac{d ^{4}}{d x ^{4}} (7 e^{x^{2}})

\frac{d}{d x} (7 e^{x^{2}}) = 14 e^{x^{2}} x

= \frac{d ^{3}}{d x ^{3}} (14 e^{x^{2}} x)

\frac{d}{d x} (14 e^{x^{2}} x) = 14 (2 e^{x^{2}} x^{2} + e^{x^{2}})

= \frac{d ^{2}}{d x ^{2}} (14 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

\frac{d}{d x} (14 (2 e^{x^{2}} x^{2} + e^{x^{2}})) = 14 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

= \frac{d}{d x} (14 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x))

\frac{d}{d x} (14 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)) = 14 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

= 14 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

y^{^{'}} + 5 x^{- 1} y = x^{6}

x \to 3 lim (\frac{3}{x - 3})

ln (7 - x^{2})

n = 0 \sum \infty (\frac{1}{6})^{n + 1}

x \to \infty lim ((1 - \frac{1}{2 x})^{2 x})

What is (d^4)/(dx^4)(7e^{x^2}) ?
The answer to (d^4)/(dx^4)(7e^{x^2}) is 14(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})