What is the solution for y^{''}+9y=5sin(3x) ?

The solution for y^{''}+9y=5sin(3x) is y=c_{1}cos(3x)+c_{2}sin(3x)-(5xcos(3x))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+9y=5sin(3x)

y^{^{''}} + 9 y = 5 sin (3 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) - \frac{5 x cos ( 3 x )}{6}

Solution steps

y^{''} (x) + 9 y = 5 sin (3 x)

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) - \frac{5 x cos ( 3 x )}{6}

y = c_{1} cos (3 x) + c_{2} sin (3 x) - \frac{5 x cos ( 3 x )}{6}

y^{^{''}} - 5 y^{^{'}} + 6 = 0

x^{^{''}} + 2 x^{^{'}} + x = 2 t e^{- t}

y^{^{''}} + y = 2 t

\frac{1}{6} y^{^{''}} + 6 y = tan (6 t) - \frac{1}{2} e^{t}

2 y^{^{''}} + 3 y^{^{'}} - 5 y = 2 cos (x)

What is the solution for y^{''}+9y=5sin(3x) ?
The solution for y^{''}+9y=5sin(3x) is y=c_{1}cos(3x)+c_{2}sin(3x)-(5xcos(3x))/6