What is the solution for d(x)=(100)/(sqrt(pi))e^{-100x^2(x)^2} ?

The solution for d(x)=(100)/(sqrt(pi))e^{-100x^2(x)^2} is x(x)=c_{1}+integral of 1/(sqrt(pi))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d(x)=(100)/(sqrt(pi))e^{-100x^2(x)^2}

d (x) = \frac{100}{π} e^{- 100 x^{2} (x)^{2}}

x (x) = c_{1} + \int \frac{1}{π} d x

Solution steps

d x (x) = \frac{100}{π} e^{- 100 x (x)^{2} x (x)^{2}}

Solve linear ODE:

x (x) = c_{1} + \int \frac{1}{π} d x

x (x) = c_{1} + \int \frac{1}{π} d x

y^{^{''}} - y^{^{'}} = x e (x), y (0) = 2, y^{^{'}} (0) = 1

x^{^{''}} + x^{^{'}} + 12 x = 40 cos (3 t)

y^{^{''}} - 3 y^{^{'}} = e^{3 x}

y^{^{''}} - 4 y^{^{'}} + 3 y = 2 e^{t}

y^{^{'''}} - y^{^{''}} + y^{^{'}} - y = 9 e^{- x}

What is the solution for d(x)=(100)/(sqrt(pi))e^{-100x^2(x)^2} ?
The solution for d(x)=(100)/(sqrt(pi))e^{-100x^2(x)^2} is x(x)=c_{1}+integral of 1/(sqrt(pi))