What is the derivative of-sin(2x) ?

The derivative of-sin(2x) is -cos(2x)*2

What is the first derivative of-sin(2x) ?

The first derivative of-sin(2x) is -cos(2x)*2

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derivative of

- sin (2 x)

- cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (- sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - cos (2 x) \cdot 2

n = 0 \sum \infty 6

x \to \infty lim (π)

x = 4 y^{3}, x = 4 y^{2}

x \to 0 lim (ln (1 + 3 x))

\int \frac{1}{x \cdot x - 1} d x

What is the derivative of-sin(2x) ?
The derivative of-sin(2x) is -cos(2x)*2
What is the first derivative of-sin(2x) ?
The first derivative of-sin(2x) is -cos(2x)*2