What is (\partial)/(\partial x)(9x+y+7xy) ?

The answer to (\partial)/(\partial x)(9x+y+7xy) is 7y+9

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(\partial)/(\partial x)(9x+y+7xy)

\frac{\partial}{\partial x} (9 x + y + 7 x y)

7 y + 9

Solution steps

\frac{\partial}{\partial x} (9 x + y + 7 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9 x) + \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (7 x y)

\frac{\partial}{\partial x} (9 x) = 9

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (7 x y) = 7 y

= 9 + 0 + 7 y

Simplify

= 7 y + 9

f^{^{'}} (x) = 1 - 2 x

x \to \infty lim (x^{2} + 5 x)

\frac{d}{d x} (3 x + 6)

\int (x^{8} - 16)^{9} x^{7} d x

(e^{\frac{t}{2}} - e)^{- \frac{1}{3}}

What is (\partial)/(\partial x)(9x+y+7xy) ?
The answer to (\partial)/(\partial x)(9x+y+7xy) is 7y+9