What is the solution for 12y^{''}+29y^'-11y=-9 ?

The solution for 12y^{''}+29y^'-11y=-9 is y=c_{1}e^{t/3}+c_{2}e^{-(11t)/4}+9/11

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12y^{''}+29y^'-11y=-9

12 y^{^{''}} + 29 y^{^{'}} - 11 y = - 9

y = c_{1} e^{\frac{t}{3}} + c_{2} e^{- \frac{11 t}{4}} + \frac{9}{11}

Solution steps

12 y^{''} (t) + 29 y^{'} (t) - 11 y = - 9

Solve linear ODE:

y = c_{1} e^{\frac{t}{3}} + c_{2} e^{- \frac{11 t}{4}} + \frac{9}{11}

y = c_{1} e^{\frac{t}{3}} + c_{2} e^{- \frac{11 t}{4}} + \frac{9}{11}

y^{^{''}} - 9 y = 2

y^{^{''}} - y = - 10 t + 4

y^{^{''}} - 10 y^{^{'}} + 25 y = e^{5} x ln (4 + x^{2})

\frac{d ^{2} y}{d x ^{2}} + y = cot (x)

y^{^{''}} + 4 y^{^{'}} + 3 y = 5 e^{- 3 t}, y (0) = 1, y^{^{'}} (0) = 0

What is the solution for 12y^{''}+29y^'-11y=-9 ?
The solution for 12y^{''}+29y^'-11y=-9 is y=c_{1}e^{t/3}+c_{2}e^{-(11t)/4}+9/11