What is the derivative of sqrt(x)+\sqrt[7]{x} ?

The derivative of sqrt(x)+\sqrt[7]{x} is 1/(2sqrt(x))+1/(7x^{6/7)}

What is the first derivative of sqrt(x)+\sqrt[7]{x} ?

The first derivative of sqrt(x)+\sqrt[7]{x} is 1/(2sqrt(x))+1/(7x^{6/7)}

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derivative of

\frac{1}{2 x} + \frac{1}{7 x ^{\frac{6}{7}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} + \frac{1}{7 x ^{\frac{6}{7}}}

f (x) = (4 x - 2 x^{3}) (4 + x)

\int_{0}^{3} x^{2} - 1 d x

y = sin (x)

(- 3, 9), (2, - 1)

What is the derivative of sqrt(x)+\sqrt[7]{x} ?
The derivative of sqrt(x)+\sqrt[7]{x} is 1/(2sqrt(x))+1/(7x^{6/7)}
What is the first derivative of sqrt(x)+\sqrt[7]{x} ?
The first derivative of sqrt(x)+\sqrt[7]{x} is 1/(2sqrt(x))+1/(7x^{6/7)}