What is the solution for y^{''}+36y=csc^2(6x) ?

The solution for y^{''}+36y=csc^2(6x) is y=c_{1}cos(6x)+c_{2}sin(6x)+(-ln(tan(3x))cos(6x)-1)/(36)

Popular >

y^{''}+36y=csc^2(6x)

y^{^{''}} + 36 y = csc^{2} (6 x)

y = c_{1} cos (6 x) + c_{2} sin (6 x) + \frac{- ln ( tan ( 3 x ) ) cos ( 6 x ) - 1}{36}

Solution steps

y^{''} (x) + 36 y = csc^{2} (6 x)

Solve linear ODE:

y = c_{1} cos (6 x) + c_{2} sin (6 x) + \frac{- ln ( tan ( 3 x ) ) cos ( 6 x ) - 1}{36}

y = c_{1} cos (6 x) + c_{2} sin (6 x) + \frac{- ln ( tan ( 3 x ) ) cos ( 6 x ) - 1}{36}

y^{^{''}} + 6 y^{^{'}} - 40 y = 1 - 3 x + x^{2}

y^{^{''}} + 10 y^{^{'}} + 25 y = e^{2 x}, y (0) = 0, y^{^{'}} (0) = 0

y^{^{''}} + 6 y^{^{'}} + 45 y = 6, y (0) = 5, y^{^{'}} (0) = 9

y^{^{''}} + 5 y^{^{'}} + 4 y = 3 e^{- 5 x}, y (0) = 5, y^{^{'}} (0) = 3

y^{^{''}} - 4 y^{^{'}} + 3 y = 5 e^{3 t}

What is the solution for y^{''}+36y=csc^2(6x) ?
The solution for y^{''}+36y=csc^2(6x) is y=c_{1}cos(6x)+c_{2}sin(6x)+(-ln(tan(3x))cos(6x)-1)/(36)