What is the solution for y^'=(1-y^2)/y ?

The solution for y^'=(1-y^2)/y is y=sqrt(-e^{-2t-c_{1)}+1},y=-sqrt(-e^{-2t-c_{1)}+1}

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y^'=(1-y^2)/y

y^{^{'}} = \frac{1 - y ^{2}}{y}

y = - e^{- 2 t - c_{1}} + 1, y = - - e^{- 2 t - c_{1}} + 1

Solution steps

y^{'} (t) = \frac{1 - y ^{2}}{y}

Solve separable ODE:

y = - e^{- 2 t - c_{1}} + 1, y = - - e^{- 2 t - c_{1}} + 1

y = - e^{- 2 t - c_{1}} + 1, y = - - e^{- 2 t - c_{1}} + 1

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What is the solution for y^'=(1-y^2)/y ?
The solution for y^'=(1-y^2)/y is y=sqrt(-e^{-2t-c_{1)}+1},y=-sqrt(-e^{-2t-c_{1)}+1}