What is the derivative of (1+e^x)/(1-e^x) ?

The derivative of (1+e^x)/(1-e^x) is (2e^x)/((1-e^x)^2)

What is the first derivative of (1+e^x)/(1-e^x) ?

The first derivative of (1+e^x)/(1-e^x) is (2e^x)/((1-e^x)^2)

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derivative of

\frac{1 + e ^{x}}{1 - e ^{x}}

\frac{2 e ^{x}}{( 1 - e ^{x} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1 + e ^{x}}{1 - e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 + e ^{x} ) ( 1 - e ^{x} ) - \frac{d}{d x} ( 1 - e ^{x} ) ( 1 + e ^{x} )}{( 1 - e ^{x} ) ^{2}}

\frac{d}{d x} (1 + e^{x}) = e^{x}

\frac{d}{d x} (1 - e^{x}) = - e^{x}

= \frac{e ^{x} ( 1 - e ^{x} ) - ( - e ^{x} ) ( 1 + e ^{x} )}{( 1 - e ^{x} ) ^{2}}

Simplify

\frac{e ^{x} ( 1 - e ^{x} ) - ( - e ^{x} ) ( 1 + e ^{x} )}{( 1 - e ^{x} ) ^{2}} : \frac{2 e ^{x}}{( 1 - e ^{x} ) ^{2}}

= \frac{2 e ^{x}}{( 1 - e ^{x} ) ^{2}}

\frac{d}{d x} ((\frac{x + 5}{x - 5})^{5})

\int sin (3 x) tan (3 x) d x

n = 2 \sum \infty n e^{- 2 n}

f (x) = sin (2 x^{2})

\int_{0}^{2} 2 π x (1 + \frac{x ^{2}}{2}) d x

What is the derivative of (1+e^x)/(1-e^x) ?
The derivative of (1+e^x)/(1-e^x) is (2e^x)/((1-e^x)^2)
What is the first derivative of (1+e^x)/(1-e^x) ?
The first derivative of (1+e^x)/(1-e^x) is (2e^x)/((1-e^x)^2)