What is the derivative of f(x)=sin(2x^2) ?

The derivative of f(x)=sin(2x^2) is cos(2x^2)*4x

What is the first derivative of f(x)=sin(2x^2) ?

The first derivative of f(x)=sin(2x^2) is cos(2x^2)*4x

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derivative of

f (x) = sin (2 x^{2})

cos (2 x^{2}) \cdot 4 x

Solution steps

\frac{d}{d x} (sin (2 x^{2}))

Apply the chain rule:

cos (2 x^{2}) \frac{d}{d x} (2 x^{2})

= cos (2 x^{2}) \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (2 x^{2}) = 4 x

= cos (2 x^{2}) \cdot 4 x

\int_{0}^{2} 2 π x (1 + \frac{x ^{2}}{2}) d x

x \to 1 lim (x^{2} + 8 x - 2)

\frac{d}{d x} (2 x^{2} cos (2 x))

y = 2 cos (x), at x = \frac{π}{3}

y^{2} + 5 x = x^{2} y - 5, (3, 5)

What is the derivative of f(x)=sin(2x^2) ?
The derivative of f(x)=sin(2x^2) is cos(2x^2)*4x
What is the first derivative of f(x)=sin(2x^2) ?
The first derivative of f(x)=sin(2x^2) is cos(2x^2)*4x