What is the tangent of y=2cos(x),\at x= pi/3 ?

The tangent of y=2cos(x),\at x= pi/3 is y=-sqrt(3)x+1+pi/(sqrt(3))

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tangent of y=2cos(x),\at x= pi/3

tangent of

y = 2 cos (x), at x = \frac{π}{3}

y = - 3 x + 1 + \frac{π}{3}

Solution steps

Find the tangent point:

(\frac{π}{3}, 1)

Find the slope of

y = 2 cos (x) : \frac{d y}{d x} = - 2 sin (x)

Compute the slope of

y = 2 cos (x)

x = \frac{π}{3} : m = - 3

Find the line with slope m=

- 3

and passing through

(\frac{π}{3}, 1) : y = - 3 x + 1 + \frac{π}{3}

y = - 3 x + 1 + \frac{π}{3}

y^{2} + 5 x = x^{2} y - 5, (3, 5)

x = y^{2}, x = 3 - 2 y^{2}

\frac{d}{d x} (x^{4} x)

\int \frac{3 x}{x ^{4} + 6 x ^{2} + 5} d x

x \to 0 + lim ((1 + a x)^{\frac{b}{x}})

What is the tangent of y=2cos(x),\at x= pi/3 ?
The tangent of y=2cos(x),\at x= pi/3 is y=-sqrt(3)x+1+pi/(sqrt(3))