What is (\partial)/(\partial x)(2xcos(x)) ?

The answer to (\partial)/(\partial x)(2xcos(x)) is 2(cos(x)-xsin(x))

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(\partial)/(\partial x)(2xcos(x))

\frac{\partial}{\partial x} (2 x cos (x))

2 (cos (x) - x sin (x))

Solution steps

\frac{\partial}{\partial x} (2 x cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (x cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = cos (x)

= 2 (\frac{\partial}{\partial x} (x) cos (x) + \frac{\partial}{\partial x} (cos (x)) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 2 (1 \cdot cos (x) + (- sin (x)) x)

Simplify

= 2 (cos (x) - x sin (x))

x^{2} y^{^{'}} - x y + 3 y^{2} = 0

\frac{d ^{4}}{d x ^{4}} (x^{x})

\int (4 - 3 x - x) d x

\frac{d}{d x} (x^{3} - 3 x^{2} - 9 x + 11)

\int \frac{6 e ^{- 6 x}}{2 - e ^{- 6 x}} d x

What is (\partial)/(\partial x)(2xcos(x)) ?
The answer to (\partial)/(\partial x)(2xcos(x)) is 2(cos(x)-xsin(x))