What is the derivative of x^2(1-6x) ?

The derivative of x^2(1-6x) is 2x-18x^2

What is the first derivative of x^2(1-6x) ?

The first derivative of x^2(1-6x) is 2x-18x^2

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derivative of

x^{2} (1 - 6 x)

2 x - 18 x^{2}

Solution steps

\frac{d}{d x} (x^{2} (1 - 6 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = 1 - 6 x

= \frac{d}{d x} (x^{2}) (1 - 6 x) + \frac{d}{d x} (1 - 6 x) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1 - 6 x) = - 6

= 2 x (1 - 6 x) + (- 6) x^{2}

Simplify

2 x (1 - 6 x) + (- 6) x^{2} : 2 x - 18 x^{2}

= 2 x - 18 x^{2}

\frac{x}{( x ^{2} + 5 x + 6 )}, 0, 1

\int e^{- θ x} d x

\frac{d}{d x} (x + y - z)

f (x) = e^{5 x}

\int 2 x^{3} 1 + x^{2} d x

What is the derivative of x^2(1-6x) ?
The derivative of x^2(1-6x) is 2x-18x^2
What is the first derivative of x^2(1-6x) ?
The first derivative of x^2(1-6x) is 2x-18x^2