What is the solution for y^{''}+y^'=1,y(0)=1,y^'(0)=1 ?

The solution for y^{''}+y^'=1,y(0)=1,y^'(0)=1 is y=t+1

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y^{''}+y^'=1,y(0)=1,y^'(0)=1

y^{^{''}} + y^{^{'}} = 1, y (0) = 1, y^{^{'}} (0) = 1

y = t + 1

Solution steps

y^{''} (t) + y^{'} (t) = 1

Solve linear ODE:

y = t + 1

y = t + 1

D (x) = 72 - 1.8 x

y^{^{'''}} - 2 y^{^{''}} + y^{^{'}} = (3 x - 4) e^{- 2 x} - 5 e^{x}

y^{^{''}} + y^{^{'}} + y = 2 x e

\frac{d ^{2} x}{d t ^{2}} + \frac{d x}{d t} = 6 t

y^{^{''}} + 2 y^{^{'}} - 3 y = - 15 x^{2} + 26 x - 3

What is the solution for y^{''}+y^'=1,y(0)=1,y^'(0)=1 ?
The solution for y^{''}+y^'=1,y(0)=1,y^'(0)=1 is y=t+1