What is area f(x)=x^2,(1,5),5 ?

The answer to area f(x)=x^2,(1,5),5 is (126-10sqrt(5))/3+10sqrt(5)-30

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area f(x)=x^2,(1,5),5

area

f (x) = x^{2}, (1, 5), 5

\frac{126 - 10 5}{3} + 105 - 30

Decimal Notation

26.90711 \dots

Solution steps

Apply the area formula:

\int_{1}^{5} x^{2} - 5 d x

Solve

\int_{1}^{5} x^{2} - 5 d x : \frac{126 - 10 5}{3} + 105 - 30

The area is:

= \frac{126 - 10 5}{3} + 105 - 30

\frac{d}{d x} (7^{x} ln^{2} (7))

arccsc (2 x^{4} - 5)

\frac{d}{d x} (\frac{2}{3} x^{3} - 8 x - 15)

x^{2} - 11, 10 x, [- 11, 0]

x \to \infty lim (4 + \frac{3}{x})

What is area f(x)=x^2,(1,5),5 ?
The answer to area f(x)=x^2,(1,5),5 is (126-10sqrt(5))/3+10sqrt(5)-30