What is the derivative of arccsc(2x^4-5) ?

The derivative of arccsc(2x^4-5) is -(4x^3)/(sqrt((2x^4-5)^2)\sqrt{x^8-5x^4+6)}

What is the first derivative of arccsc(2x^4-5) ?

The first derivative of arccsc(2x^4-5) is -(4x^3)/(sqrt((2x^4-5)^2)\sqrt{x^8-5x^4+6)}

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derivative of

arccsc (2 x^{4} - 5)

- \frac{4 x ^{3}}{( 2 x ^{4} - 5 ) ^{2} x ^{8} - 5 x ^{4} + 6}

Solution steps

\frac{d}{d x} (arccsc (2 x^{4} - 5))

Apply the chain rule:

- \frac{1}{( 2 x ^{4} - 5 ) ^{2} ( 2 x ^{4} - 5 ) ^{2} - 1} \frac{d}{d x} (2 x^{4} - 5)

= - \frac{1}{( 2 x ^{4} - 5 ) ^{2} ( 2 x ^{4} - 5 ) ^{2} - 1} \frac{d}{d x} (2 x^{4} - 5)

\frac{d}{d x} (2 x^{4} - 5) = 8 x^{3}

= - \frac{1}{( 2 x ^{4} - 5 ) ^{2} ( 2 x ^{4} - 5 ) ^{2} - 1} \cdot 8 x^{3}

Simplify

- \frac{1}{( 2 x ^{4} - 5 ) ^{2} ( 2 x ^{4} - 5 ) ^{2} - 1} \cdot 8 x^{3} : - \frac{4 x ^{3}}{( 2 x ^{4} - 5 ) ^{2} x ^{8} - 5 x ^{4} + 6}

= - \frac{4 x ^{3}}{( 2 x ^{4} - 5 ) ^{2} x ^{8} - 5 x ^{4} + 6}

\frac{d}{d x} (\frac{2}{3} x^{3} - 8 x - 15)

x^{2} - 11, 10 x, [- 11, 0]

x \to \infty lim (4 + \frac{3}{x})

\int \frac{9 x ^{2}}{( 100 + x ^{2} ) ^{2}} d x

What is the derivative of arccsc(2x^4-5) ?
The derivative of arccsc(2x^4-5) is -(4x^3)/(sqrt((2x^4-5)^2)\sqrt{x^8-5x^4+6)}
What is the first derivative of arccsc(2x^4-5) ?
The first derivative of arccsc(2x^4-5) is -(4x^3)/(sqrt((2x^4-5)^2)\sqrt{x^8-5x^4+6)}