What is the integral of (9x^2)/((100+x^2)^2) ?

The integral of (9x^2)/((100+x^2)^2) is (9(x^2arctan(x/(10))-10x+100arctan(x/(10))))/(20(100+x^2))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (9x^2)/((100+x^2)^2)

\int \frac{9 x ^{2}}{( 100 + x ^{2} ) ^{2}} d x

\frac{9 ( x ^{2} arctan ( \frac{x}{10} ) - 10 x + 100 arctan ( \frac{x}{10} ) )}{20 ( 100 + x ^{2} )} + C

Solution steps

\int \frac{9 x ^{2}}{( 100 + x ^{2} ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int \frac{x ^{2}}{( 100 + x ^{2} ) ^{2}} d x

Apply Integral Substitution

= 9 \cdot \int \frac{u ^{2}}{10 ( u ^{2} + 1 ) ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \frac{1}{10} \cdot \int \frac{u ^{2}}{( u ^{2} + 1 ) ^{2}} d u

Take the partial fraction of

\frac{u ^{2}}{( u ^{2} + 1 ) ^{2}} : \frac{1}{u ^{2} + 1} - \frac{1}{( u ^{2} + 1 ) ^{2}}

= 9 \cdot \frac{1}{10} \cdot \int \frac{1}{u ^{2} + 1} - \frac{1}{( u ^{2} + 1 ) ^{2}} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 9 \cdot \frac{1}{10} (\int \frac{1}{u ^{2} + 1} d u - \int \frac{1}{( u ^{2} + 1 ) ^{2}} d u)

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

\int \frac{1}{( u ^{2} + 1 ) ^{2}} d u = \frac{1}{2} (arctan (u) + \frac{u}{1 + u ^{2}})

= 9 \cdot \frac{1}{10} (arctan (u) - \frac{1}{2} (arctan (u) + \frac{u}{1 + u ^{2}}))

Substitute back

u = \frac{x}{10}

= 9 \cdot \frac{1}{10} (arctan (\frac{x}{10}) - \frac{1}{2} (arctan (\frac{x}{10}) + \frac{\frac{x}{10}}{1 + ( \frac{x}{10} ) ^{2}}))

Simplify

9 \cdot \frac{1}{10} (arctan (\frac{x}{10}) - \frac{1}{2} (arctan (\frac{x}{10}) + \frac{\frac{x}{10}}{1 + ( \frac{x}{10} ) ^{2}})) : \frac{9 ( x ^{2} arctan ( \frac{x}{10} ) - 10 x + 100 arctan ( \frac{x}{10} ) )}{20 ( 100 + x ^{2} )}

= \frac{9 ( x ^{2} arctan ( \frac{x}{10} ) - 10 x + 100 arctan ( \frac{x}{10} ) )}{20 ( 100 + x ^{2} )}

Add a constant to the solution

= \frac{9 ( x ^{2} arctan ( \frac{x}{10} ) - 10 x + 100 arctan ( \frac{x}{10} ) )}{20 ( 100 + x ^{2} )} + C

\int \frac{π}{4}

\frac{\partial}{\partial x} (x^{3} e^{3 x y})

\int_{- \infty}^{0} 3^{r} d r

\int_{0}^{2} \frac{1}{1 - x} d x

\frac{d}{d x} (3 x^{2} + 4 x + 5)

What is the integral of (9x^2)/((100+x^2)^2) ?
The integral of (9x^2)/((100+x^2)^2) is (9(x^2arctan(x/(10))-10x+100arctan(x/(10))))/(20(100+x^2))+C