What is the integral from-infinity to 0 of 3^r ?

The integral from-infinity to 0 of 3^r is 1/(ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 0 of 3^r

\int_{- \infty}^{0} 3^{r} d r

\frac{1}{ln ( 3 )}

Decimal Notation

0.91023 \dots

Solution steps

\int_{- \infty}^{0} 3^{r} d r

Compute the indefinite integral:

\int 3^{r} d r = \frac{3 ^{r}}{ln ( 3 )} + C

Compute the boundaries:

\int_{- \infty}^{0} 3^{r} d r = \frac{1}{ln ( 3 )} - 0

= \frac{1}{ln ( 3 )} - 0

Simplify

= \frac{1}{ln ( 3 )}

\int_{0}^{2} \frac{1}{1 - x} d x

\frac{d}{d x} (3 x^{2} + 4 x + 5)

x \to 0 lim (\frac{x ^{2}}{1 + x ^{2}})

3 (t - π)

x \to \infty lim ((1 - 5 x)^{\frac{5}{x}})

What is the integral from-infinity to 0 of 3^r ?
The integral from-infinity to 0 of 3^r is 1/(ln(3))