What is the integral from 6 to 12 of (6e^x) ?

The integral from 6 to 12 of (6e^x) is 6(e^{12}-e^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 6 to 12 of (6e^x)

\int_{6}^{12} (6 e^{x}) d x

6 (e^{12} - e^{6})

Decimal Notation

974108.17575 \dots

Solution steps

\int_{6}^{12} 6 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{6}^{12} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 6 [e^{x}]_{6}^{12}

Compute the boundaries:

e^{12} - e^{6}

= 6 (e^{12} - e^{6})

\int \frac{9 - x}{9 + x} d x

\frac{d}{d x} (m x n + b + b^{8} x^{3} m - 5 + n x^{2} b - 2)

f (x) = \frac{e ^{2}}{x ^{2} - 2 x}

\int (\frac{7}{x}) d x

p \to 0 lim (p^{2} sin (\frac{1}{p}))

What is the integral from 6 to 12 of (6e^x) ?
The integral from 6 to 12 of (6e^x) is 6(e^{12}-e^6)