What is the derivative of mxn+b+b^8x^3m-5+nx^2b-2 ?

The derivative of mxn+b+b^8x^3m-5+nx^2b-2 is 3b^8mx^2+2bnx+mn

What is the first derivative of mxn+b+b^8x^3m-5+nx^2b-2 ?

The first derivative of mxn+b+b^8x^3m-5+nx^2b-2 is 3b^8mx^2+2bnx+mn

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\frac{d}{d x} (m x n + b + b^{8} x^{3} m - 5 + n x^{2} b - 2)

3 b^{8} m x^{2} + 2 bn x + mn

Solution steps

\frac{d}{d x} (m x n + b + b^{8} x^{3} m - 5 + n x^{2} b - 2)

Simplify

m x n + b + b^{8} x^{3} m - 5 + n x^{2} b - 2 : b^{8} m x^{3} + bn x^{2} + mn x + b - 7

= \frac{d}{d x} (b^{8} m x^{3} + bn x^{2} + mn x + b - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (b^{8} m x^{3}) + \frac{d}{d x} (bn x^{2}) + \frac{d}{d x} (mn x) + \frac{d b}{d x} - \frac{d}{d x} (7)

\frac{d}{d x} (b^{8} m x^{3}) = 3 b^{8} m x^{2}

\frac{d}{d x} (bn x^{2}) = 2 bn x

\frac{d}{d x} (mn x) = mn

\frac{d b}{d x} = 0

\frac{d}{d x} (7) = 0

= 3 b^{8} m x^{2} + 2 bn x + mn + 0 - 0

Simplify

= 3 b^{8} m x^{2} + 2 bn x + mn

f (x) = \frac{e ^{2}}{x ^{2} - 2 x}

\int (\frac{7}{x}) d x

p \to 0 lim (p^{2} sin (\frac{1}{p}))

y^{^{''}} - 18 y^{^{'}} + 117 y = 0

x \to \frac{1}{2} lim (\frac{x + 4}{2 x})

What is the derivative of mxn+b+b^8x^3m-5+nx^2b-2 ?
The derivative of mxn+b+b^8x^3m-5+nx^2b-2 is 3b^8mx^2+2bnx+mn
What is the first derivative of mxn+b+b^8x^3m-5+nx^2b-2 ?
The first derivative of mxn+b+b^8x^3m-5+nx^2b-2 is 3b^8mx^2+2bnx+mn