What is the solution for (dN)/(dt)=N(1-0.0002N) ?

The solution for (dN)/(dt)=N(1-0.0002N) is N=-(e^{t+c_{1}})/(1-0.0002e^{t+c_{1)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dN)/(dt)=N(1-0.0002N)

\frac{d N}{d t} = N (1 - 0.0002 N)

N = - \frac{e ^{t + c_{1}}}{1 - 0.0002 e ^{t + c_{1}}}

Solution steps

\frac{d N}{d t} = N (1 - 0.0002 N)

Solve separable ODE:

N = - \frac{e ^{t + c_{1}}}{1 - 0.0002 e ^{t + c_{1}}}

N = - \frac{e ^{t + c_{1}}}{1 - 0.0002 e ^{t + c_{1}}}

\frac{d}{d x} (c_{1} cos (2 x) + c_{2} sin (2 x))

\frac{d}{d x} (sec (\frac{1}{2} x) tan (\frac{1}{2} x))

\frac{d}{d x} (\frac{a}{x ^{2} + b})

y = x^{8}

\frac{d}{d y} (x^{2} + 2 x y + y^{2})

What is the solution for (dN)/(dt)=N(1-0.0002N) ?
The solution for (dN)/(dt)=N(1-0.0002N) is N=-(e^{t+c_{1}})/(1-0.0002e^{t+c_{1)}}