What is the integral from 0 to x of e^{t^2} ?

The integral from 0 to x of e^{t^2} is (sqrt(pi))/2 \erfi(x)

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integral from 0 to x of e^{t^2}

\int_{0}^{x} e^{t^{2}} d t

\frac{π}{2} erfi (x)

Solution steps

\int_{0}^{x} e^{t^{2}} d t

Use the nonelementary integral:

\int e^{t^{2}} d t = \frac{π}{2} erfi (t)

= [\frac{π}{2} erfi (t)]_{0}^{x}

Compute the boundaries:

\frac{π}{2} erfi (x)

= \frac{π}{2} erfi (x)

\int (4 + 3 x) e^{- x} d x

\frac{\partial}{\partial x} (2 x e^{x})

f (x) = 6 x + 7 x

x \to 3 lim (\frac{- 2 x}{x - 3})

\int \frac{6}{8 - 3 x} d x

What is the integral from 0 to x of e^{t^2} ?
The integral from 0 to x of e^{t^2} is (sqrt(pi))/2 \erfi(x)