What is the derivative of 7x^6-9cos(x) ?

The derivative of 7x^6-9cos(x) is 42x^5+9sin(x)

What is the first derivative of 7x^6-9cos(x) ?

The first derivative of 7x^6-9cos(x) is 42x^5+9sin(x)

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derivative of

7 x^{6} - 9 cos (x)

42 x^{5} + 9 sin (x)

Solution steps

\frac{d}{d x} (7 x^{6} - 9 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 x^{6}) - \frac{d}{d x} (9 cos (x))

\frac{d}{d x} (7 x^{6}) = 42 x^{5}

\frac{d}{d x} (9 cos (x)) = - 9 sin (x)

= 42 x^{5} - (- 9 sin (x))

Simplify

= 42 x^{5} + 9 sin (x)

\frac{d}{d x} ((4 x^{2} + 3) (4 x - 5))

\int_{3.5}^{5} \frac{x}{8} d x

\int \frac{- 16}{4 - x ^{2}} d x

\int x (1 - x^{2})^{2} d x

What is the derivative of 7x^6-9cos(x) ?
The derivative of 7x^6-9cos(x) is 42x^5+9sin(x)
What is the first derivative of 7x^6-9cos(x) ?
The first derivative of 7x^6-9cos(x) is 42x^5+9sin(x)