What is the derivative of g(t)= 3/(4t^6) ?

The derivative of g(t)= 3/(4t^6) is -9/(2t^7)

What is the first derivative of g(t)= 3/(4t^6) ?

The first derivative of g(t)= 3/(4t^6) is -9/(2t^7)

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derivative of

g (t) = \frac{3}{4 t ^{6}}

- \frac{9}{2 t ^{7}}

Solution steps

\frac{d}{d t} (\frac{3}{4 t ^{6}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3}{4} \frac{d}{d t} (\frac{1}{t ^{6}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{3}{4} \frac{d}{d t} (t^{- 6})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{3}{4} (- 6 t^{- 6 - 1})

Simplify

\frac{3}{4} (- 6 t^{- 6 - 1}) : - \frac{9}{2 t ^{7}}

= - \frac{9}{2 t ^{7}}

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What is the derivative of g(t)= 3/(4t^6) ?
The derivative of g(t)= 3/(4t^6) is -9/(2t^7)
What is the first derivative of g(t)= 3/(4t^6) ?
The first derivative of g(t)= 3/(4t^6) is -9/(2t^7)