What is the derivative of (2x^2+1^4) ?

The derivative of (2x^2+1^4) is 16x(2x^2+1)^3

What is the first derivative of (2x^2+1^4) ?

The first derivative of (2x^2+1^4) is 16x(2x^2+1)^3

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\frac{d}{d x} ((2 x^{2} + 1)^{4})

16 x (2 x^{2} + 1)^{3}

Solution steps

\frac{d}{d x} ((2 x^{2} + 1)^{4})

Apply the chain rule:

4 (2 x^{2} + 1)^{3} \frac{d}{d x} (2 x^{2} + 1)

= 4 (2 x^{2} + 1)^{3} \frac{d}{d x} (2 x^{2} + 1)

\frac{d}{d x} (2 x^{2} + 1) = 4 x

= 4 (2 x^{2} + 1)^{3} \cdot 4 x

Simplify

= 16 x (2 x^{2} + 1)^{3}

x^{\frac{1}{4}}

f (x) = \frac{2 x + 2}{x + 7}

t cos (t)

x \to 1 lim (\frac{x}{( x ^{3} - 1 )})

\frac{d}{d x} (64 e^{- 4 x})

What is the derivative of (2x^2+1^4) ?
The derivative of (2x^2+1^4) is 16x(2x^2+1)^3
What is the first derivative of (2x^2+1^4) ?
The first derivative of (2x^2+1^4) is 16x(2x^2+1)^3