What is the derivative of 64e^{-4x} ?

The derivative of 64e^{-4x} is -256e^{-4x}

What is the first derivative of 64e^{-4x} ?

The first derivative of 64e^{-4x} is -256e^{-4x}

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\frac{d}{d x} (64 e^{- 4 x})

- 256 e^{- 4 x}

Solution steps

\frac{d}{d x} (64 e^{- 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 64 \frac{d}{d x} (e^{- 4 x})

Apply the chain rule:

e^{- 4 x} \frac{d}{d x} (- 4 x)

= e^{- 4 x} \frac{d}{d x} (- 4 x)

\frac{d}{d x} (- 4 x) = - 4

= 64 e^{- 4 x} (- 4)

Simplify

= - 256 e^{- 4 x}

\frac{\partial}{\partial y} (\frac{x y}{x ^{2} - y ^{2}})

y = 4 x, x = 4, x = 9

x \to + 0 lim (\frac{1}{x} cos (\frac{1}{x}))

\int \frac{1}{t ^{2} + 4} d t

\frac{d y}{d x} = \frac{x ^{4}}{y}

What is the derivative of 64e^{-4x} ?
The derivative of 64e^{-4x} is -256e^{-4x}
What is the first derivative of 64e^{-4x} ?
The first derivative of 64e^{-4x} is -256e^{-4x}