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Popular >

y^{''}+2y^'=c

Solution

y^{^{''}} + 2 y^{^{'}} = c

Solution

y = c_{1} + c_{2} e^{- 2 t} + \frac{c t}{2}

Solution steps

y^{''} (t) + 2 y^{'} (t) = c

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 t} + \frac{c t}{2}

y = c_{1} + c_{2} e^{- 2 t} + \frac{c t}{2}

Graph

Popular Examples

2y^{''}+8y^'+80y=30,y(0)=0,y^'(0)=0

2 y^{^{''}} + 8 y^{^{'}} + 80 y = 30, y (0) = 0, y^{^{'}} (0) = 0

q^{''}+q^'+1/(0.05)=80t

q^{^{''}} + q^{^{'}} + \frac{1}{0.05} = 80 t

y^{''}-y=-11t+1

y^{^{''}} - y = - 11 t + 1

y^{''}-3y^'-46y=2sin(t)

y^{^{''}} - 3 y^{^{'}} - 46 y = 2 sin (t)

y^{''}-y=-11t+4

y^{^{''}} - y = - 11 t + 4

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+2y^'=c ?
The solution for y^{''}+2y^'=c is y=c_{1}+c_{2}e^{-2t}+(ct)/2