What is (\partial)/(\partial y)((xy)/(x^2-y^2)) ?

The answer to (\partial)/(\partial y)((xy)/(x^2-y^2)) is (x(x^2+y^2))/((x^2-y^2)^2)

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(\partial)/(\partial y)((xy)/(x^2-y^2))

\frac{\partial}{\partial y} (\frac{x y}{x ^{2} - y ^{2}})

\frac{x ( x ^{2} + y ^{2} )}{( x ^{2} - y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{x y}{x ^{2} - y ^{2}})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial y} (\frac{y}{x ^{2} - y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= x \frac{\frac{\partial}{\partial y} ( y ) ( x ^{2} - y ^{2} ) - \frac{\partial}{\partial y} ( x ^{2} - y ^{2} ) y}{( x ^{2} - y ^{2} ) ^{2}}

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (x^{2} - y^{2}) = - 2 y

= x \frac{1 \cdot ( x ^{2} - y ^{2} ) - ( - 2 y ) y}{( x ^{2} - y ^{2} ) ^{2}}

Simplify

x \frac{1 \cdot ( x ^{2} - y ^{2} ) - ( - 2 y ) y}{( x ^{2} - y ^{2} ) ^{2}} : \frac{x ( x ^{2} + y ^{2} )}{( x ^{2} - y ^{2} ) ^{2}}

= \frac{x ( x ^{2} + y ^{2} )}{( x ^{2} - y ^{2} ) ^{2}}

y = 4 x, x = 4, x = 9

x \to + 0 lim (\frac{1}{x} cos (\frac{1}{x}))

\int \frac{1}{t ^{2} + 4} d t

\frac{d y}{d x} = \frac{x ^{4}}{y}

x \to 2 lim (x^{2} + 2 x - 5)

What is (\partial)/(\partial y)((xy)/(x^2-y^2)) ?
The answer to (\partial)/(\partial y)((xy)/(x^2-y^2)) is (x(x^2+y^2))/((x^2-y^2)^2)