What is inverse oflaplace (-1)/s ?

The answer to inverse oflaplace (-1)/s is -\H(t)

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inverse oflaplace (-1)/s

inverse laplace

\frac{- 1}{s}

- H (t)

Solution steps

L^{- 1} {\frac{- 1}{s}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s}} = a H (t)

Where

H (t)

is Heaviside step function

= - 1 \cdot H (t)

= - H (t)

\int - cos (3 x) d x

\frac{1}{x - 1}, 22

\frac{d}{d x} (8 (1 - x)^{- 2})

\frac{d}{d x} (\frac{1}{2} x^{6} - 3 x^{4} + x)

\int e^{(a - s) t} d t

What is inverse oflaplace (-1)/s ?
The answer to inverse oflaplace (-1)/s is -\H(t)