What is the solution for y^{''}+17y=5e^x ?

The solution for y^{''}+17y=5e^x is y=c_{1}cos(sqrt(17)x)+c_{2}sin(sqrt(17)x)+5/18 e^x

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y^{''}+17y=5e^x

y^{^{''}} + 17 y = 5 e^{x}

y = c_{1} cos (17 x) + c_{2} sin (17 x) + \frac{5}{18} e^{x}

Solution steps

y^{''} (x) + 17 y = 5 e^{x}

Solve linear ODE:

y = c_{1} cos (17 x) + c_{2} sin (17 x) + \frac{5}{18} e^{x}

y = c_{1} cos (17 x) + c_{2} sin (17 x) + \frac{5}{18} e^{x}

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{( 9 + e ^{x} )}

y^{^{''}} + 10 y^{^{'}} + 25 y = 128 e^{3 t}

d, d (x) = lo g_{10} (\frac{x + 4}{x - 1})

y^{^{''}} + 4 y^{^{'}} + y = 4

a y^{^{''}} + b y^{^{'}} = 1

What is the solution for y^{''}+17y=5e^x ?
The solution for y^{''}+17y=5e^x is y=c_{1}cos(sqrt(17)x)+c_{2}sin(sqrt(17)x)+5/18 e^x