What is the limit as x approaches 1 of 2|x-1|-1 ?

The limit as x approaches 1 of 2|x-1|-1 is -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of 2|x-1|-1

x \to 1 lim (2 ∣ x - 1 ∣ - 1)

- 1

Solution steps

x \to 1 lim (2 ∣ x - 1 ∣ - 1)

Plug in the value

x = 1

= 2 ∣ 1 - 1 ∣ - 1

Simplify

2 ∣ 1 - 1 ∣ - 1 : - 1

= - 1

a y^{^{''}} + b y = 0

sin (\frac{π x}{2})

2 sin (3 x)

\int \frac{sin ( \frac{1}{x ^{3}} )}{x ^{4}} d x

\frac{\partial}{\partial x} (\frac{( 4 x - 4 y )}{4 x + 4 y})

What is the limit as x approaches 1 of 2|x-1|-1 ?
The limit as x approaches 1 of 2|x-1|-1 is -1