What is the derivative of 2sin(3x) ?

The derivative of 2sin(3x) is 6cos(3x)

What is the first derivative of 2sin(3x) ?

The first derivative of 2sin(3x) is 6cos(3x)

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derivative of

2 sin (3 x)

6 cos (3 x)

Solution steps

\frac{d}{d x} (2 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 2 cos (3 x) \cdot 3

Simplify

= 6 cos (3 x)

\int \frac{sin ( \frac{1}{x ^{3}} )}{x ^{4}} d x

\frac{\partial}{\partial x} (\frac{( 4 x - 4 y )}{4 x + 4 y})

\frac{\partial}{\partial x} (tan (8 + 2 x^{2} y^{4} z^{2}))

\frac{\partial}{\partial x} (324 x^{2} - 324 x y + 81 y^{2})

4 cos (3 x), 4 sin (6 x), 0, \frac{π}{6}

What is the derivative of 2sin(3x) ?
The derivative of 2sin(3x) is 6cos(3x)
What is the first derivative of 2sin(3x) ?
The first derivative of 2sin(3x) is 6cos(3x)