What is the solution for 16y^{''}-24y^'+9y=0,y(0)=3,y^'(0)=5 ?

The solution for 16y^{''}-24y^'+9y=0,y(0)=3,y^'(0)=5 is y=3e^{(3t)/4}+(11e^{(3t)/4}t)/(4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16y^{''}-24y^'+9y=0,y(0)=3,y^'(0)=5

16 y^{^{''}} - 24 y^{^{'}} + 9 y = 0, y (0) = 3, y^{^{'}} (0) = 5

y = 3 e^{\frac{3 t}{4}} + \frac{11 e ^{\frac{3 t}{4}} t}{4}

Solution steps

16 y^{''} (t) - 24 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = 3 e^{\frac{3 t}{4}} + \frac{11 e ^{\frac{3 t}{4}} t}{4}

y = 3 e^{\frac{3 t}{4}} + \frac{11 e ^{\frac{3 t}{4}} t}{4}

y^{^{'''}} - 3 y^{^{'}} + 2 y = 0

3 y^{^{''}} - 5 y^{^{'}} - 12 y = 0

y^{^{''}} + 2 y^{^{'}} + 2 y = 0, y (0) = 1, y^{^{'}} (0) = - 1

y^{^{''}} + cy = 0

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} + 13 y = 0

What is the solution for 16y^{''}-24y^'+9y=0,y(0)=3,y^'(0)=5 ?
The solution for 16y^{''}-24y^'+9y=0,y(0)=3,y^'(0)=5 is y=3e^{(3t)/4}+(11e^{(3t)/4}t)/(4)