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Popular >

d/(dt)((2t-1)/(2t+1))

Solution

\frac{d}{d t} (\frac{2 t - 1}{2 t + 1})

Solution

\frac{4}{( 2 t + 1 ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{2 t - 1}{2 t + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d t} ( 2 t - 1 ) ( 2 t + 1 ) - \frac{d}{d t} ( 2 t + 1 ) ( 2 t - 1 )}{( 2 t + 1 ) ^{2}}

\frac{d}{d t} (2 t - 1) = 2

\frac{d}{d t} (2 t + 1) = 2

= \frac{2 ( 2 t + 1 ) - 2 ( 2 t - 1 )}{( 2 t + 1 ) ^{2}}

Expand

2 (2 t + 1) - 2 (2 t - 1) : 4

= \frac{4}{( 2 t + 1 ) ^{2}}

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Frequently Asked Questions (FAQ)

What is the d/(dt)((2t-1)/(2t+1)) ?
The d/(dt)((2t-1)/(2t+1)) is 4/((2t+1)^2)
What is the first d/(dt)((2t-1)/(2t+1)) ?
The first d/(dt)((2t-1)/(2t+1)) is 4/((2t+1)^2)