What is the solution for y^{''}+y^'-15y=0 ?

The solution for y^{''}+y^'-15y=0 is y=c_{1}e^{((-1+sqrt(61))t)/2}+c_{2}e^{((-1-sqrt(61))t)/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+y^'-15y=0

y^{^{''}} + y^{^{'}} - 15 y = 0

y = c_{1} e^{\frac{( - 1 + 61 ) t}{2}} + c_{2} e^{\frac{( - 1 - 61 ) t}{2}}

Solution steps

y^{''} (t) + y^{'} (t) - 15 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( - 1 + 61 ) t}{2}} + c_{2} e^{\frac{( - 1 - 61 ) t}{2}}

y = c_{1} e^{\frac{( - 1 + 61 ) t}{2}} + c_{2} e^{\frac{( - 1 - 61 ) t}{2}}

6 y^{^{''''}} + 11 y^{^{''}} + 4 y = 0

y^{^{''''}} - 4 y^{^{'''}} + 5 y^{^{''}} - 4 y^{^{'}} + 4 y = 0

u^{^{''}} + 4 u^{^{'}} + 4 H (t) = 0

x^{^{''}} - 8 x = 0

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} - 12 y = 0

What is the solution for y^{''}+y^'-15y=0 ?
The solution for y^{''}+y^'-15y=0 is y=c_{1}e^{((-1+sqrt(61))t)/2}+c_{2}e^{((-1-sqrt(61))t)/2}